![]() ![]() Note that the average speed is not ! (65 mi/h + 55 mi/h). We find the distance traveled at the lower speed fromĥ5 mi/h = d 2 /(1.33 h), which gives d 2 = 73 mi.ĭ = d 1 + d 2 = 130 mi + 73 mi = 203 mi. ( a) We find the elapsed time before the speed change fromĦ5 mi/h = (130 mi)/ t 1, which gives t 1 = 2.0 h.
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